(y^2+3y-5)+(-y^2+3y-5)=8

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Solution for (y^2+3y-5)+(-y^2+3y-5)=8 equation:


Simplifying
(y2 + 3y + -5) + (-1y2 + 3y + -5) = 8

Reorder the terms:
(-5 + 3y + y2) + (-1y2 + 3y + -5) = 8

Remove parenthesis around (-5 + 3y + y2)
-5 + 3y + y2 + (-1y2 + 3y + -5) = 8

Reorder the terms:
-5 + 3y + y2 + (-5 + 3y + -1y2) = 8

Remove parenthesis around (-5 + 3y + -1y2)
-5 + 3y + y2 + -5 + 3y + -1y2 = 8

Reorder the terms:
-5 + -5 + 3y + 3y + y2 + -1y2 = 8

Combine like terms: -5 + -5 = -10
-10 + 3y + 3y + y2 + -1y2 = 8

Combine like terms: 3y + 3y = 6y
-10 + 6y + y2 + -1y2 = 8

Combine like terms: y2 + -1y2 = 0
-10 + 6y + 0 = 8
-10 + 6y = 8

Solving
-10 + 6y = 8

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 6y = 8 + 10

Combine like terms: -10 + 10 = 0
0 + 6y = 8 + 10
6y = 8 + 10

Combine like terms: 8 + 10 = 18
6y = 18

Divide each side by '6'.
y = 3

Simplifying
y = 3

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